Question

Find the distance between the points A(2, 3) and B(8, 11), and the midpoint of AB.

Solution

1. Distance = √((8 - 2)^2 + (11 - 3)^2) = √(36 + 64) = √100 = 10 units.
2. Midpoint = ((2 + 8) / 2, (3 + 11) / 2) = (5, 7).
3. Therefore, AB = 10 units and the midpoint is (5, 7).